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A pressure of 10 MPa is applied to 0.25m3 of a liquid, causing a volume reduction of 0.005 cm3. Determine the bulk modulus of elasticity.

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Answer:

K = 500 x 10⁶ MPa

Step-by-step explanation:

Given that

P = 10 MPa

V= 0.25 m ³

Reduction in the volume ,ΔV=- 0.005 cm³

We know that 1 m = 1000 cm

ΔV=- 0.005 cm³ = - 0.005 x 10⁻⁶ m³

We know that bulk modulus given as


K=-(P)/((\Delta V)/(V))

Now by putting the values


K=-(10)/((-0.005* 10^(-6))/(0.25))

We get

K = 500 x 10⁶ MPa

Therefore the bulk modulus of the elasticity will be 500 x 10⁶ MPa.

User Herlon Aguiar
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