Answer:
31.62 kJ
Step-by-step explanation:
Step 1: identify the given parameters
mass of ice = 0.2 kg
Initial temperature of ice (T₁) = 25 ⁰C
Final temperature of ice (T₂) = 100 ⁰C
specific heat capacity of ice (Cp) = 2.108 kJ/kgK
Heat required to convert the ice (H) = ?
Step 2: calculate the amount of heat required to convert the ice
H = M*Cp*ΔT
H = 0.2*2.108*(100-25)
H = 31.62 kJ
Note: the aluminum container is in thermal equilibrium with the initial frozen water, hence they are at the same temperature. For this reason, the container will not affect the temperature of the frozen ice.