Answer:
The tension of the wire = 3.5×10³ N
Step-by-step explanation:
The frequency of a string is given as
f = √(T/m)/2πL.................... Equation 1
Where f = fundamental frequency, L = length of the steel wire, T = Tension of the steel wire, m = mass of the steel wire
Making T the subject of the equation above.
T = f²4π²L²m..................... Equation 2
Given: f = 261.6 Hz, L = 0.6 m, m = 3.6×10⁻³ kg and π = 3.143.
Substituting these values into equation 2,
T = 261.6²×4×(3.143)²×(0.6)²×3.6×10⁻³
T = 68434.56×4×9.878×0.36×3.6×10⁻³
T = 3504366.3×10⁻³
T = 3504.37 N
T ≈ 3.5×10³ N
Thus the tension of the wire = 3.5×10³ N