Question

A roller coaster starts from rest at the top ofan 18m hill.

The car travels to the bottom of the hill andcontinues up the next
hill that is 10.0m high.

Answer 1

v= 12.522 m/s

Step-by-step explanation:

Supposing we have to find the velocity of the car

By conserving energy we can say that

Initial potential energy= Final potential energy + Final kinetic energy

So

`mgh_(initial)=mgh_(final)+0.5mv^2`

also h{initial}=18 m

h_{final}=10 m

therefore,

0.5mv^2=mg(18-10)

So

`v=√(16g)`

v= 12.522 m/s