Question

A 2.0 kg tumor is being irradiated by a radioactive source.The

tumor receives an absorbed dose of 12 Gy in a time of880 s. Each
disintegration of theradioactive source produces a particle that
enters the tumor anddelivers an energy of 0.40 MeV. Whatis the
activity N//t of
theradioactive source?

Answer 1

426136363636.36365 Bq

Step-by-step explanation:

Grays = 12

Mass = 2 kg

Time = 880

Energy = 0.4 MeV

Activity is given by

`Activity=(Grays* Mass)/(Time* 0.4)\\\Rightarrow Activity=(12* 2)/(880* 0.4* 1.6* 10^(-13))\\\Rightarrow Activity=426136363636.36365\ Bq`

The activity N//t of the radioactive source is 426136363636.36365 Bq