Question

Some believe that the positions of the planets at the time

ofbirth influence the newborn. Others deride this belief andclaim
that the gravitational force exerted on a baby by theobstetrician
is greater than that exerted by the planets. To checkthic laim,
calculate and compare the gravitational force exerted ona 3 kg
baby
a.) by a 70 kg obstetrician who is 1 m away and
roughlyapproximated as a point mass
b.) by the massive planet Jupiter (m = 2 X 1027
kg)at its closests approach to earth
( = 6 X 1011 m)
c.) by Jupiter at its greatest distance from Earth ( = 9
X1011 m)
d.) Is the claim correct?

Answer 1

`1.4007* 10^(-8)\ N`

`1.50075* 10^(-6)\ N`

`0.000000667\ N`

Step-by-step explanation:

`m_1` = Mass of baby = 3 kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Distance between objects

Gravitational force of attraction is given by

`F=(Gm_1m_2)/(r^2)\\\Rightarrow F=(6.67* 10^(-11)* 70* 3)/(1^2)\\\Rightarrow F=1.4007* 10^(-8)\ N`

The force between baby and obstetrician is
`1.4007* 10^(-8)\ N`

`F=(6.67* 10^(-11)* 3* 2.7* 10^(27))/((6* 10^(11))^2)\\\Rightarrow F=1.50075* 10^(-6)\ N`

The force between the baby and Jupiter is
`1.50075* 10^(-6)\ N`

`F=(6.67* 10^(-11)* 3* 2.7* 10^(27))/((9* 10^(11))^2)\\\Rightarrow F=0.000000667\ N`

The force between the baby and Jupiter is
`0.000000667\ N`