Answer:
I = 0.0025 kg.m²
Step-by-step explanation:
Given that
m= 2 kg
Diameter ,d= 0.1 m
Radius ,


R=0.05 m
The moment of inertia of the cylinder about it's axis same as the disc and it is given as

Now by putting the all values

I = 0.0025 kg.m²
Therefore we can say that the moment of inertia of the cylinder will be 0.0025 kg.m².