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An organ pipe is open at both ends. It is producing sound

atits third harmonic, the frequency of which is 262 Hz. The speed
ofsound is 343 m/s. What is the length of the pipe?

1 Answer

3 votes

To solve this problem we will apply the concepts related to the wavelength of its third harmonic.

It describes that the wavelength is equivalent to


\lambda = (2)/(3)L

Here,


\lambda = Wavelength

The wavelength is in turn described as a function that depends on the change of the speed as a function of the frequency, that is to say


\lambda = (v)/(f)

In this case the speed is equivalent to the speed of sound and the frequency was previously given, therefore


\lambda = (343)/(262)


\lambda = 1.3091m

Finally the length of the pipe would be


L= (3)/(2)(1.3091)


L = 1.963m

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