Answer:
Margin of error = 0.0444
The resulting interval = 0.5156 to 0.6044
Explanation:
Data provided in the question:
Sample size, n = 500
Number of women answer yes = 280
Probability of women answering yes, p = 280 ÷ 500
= 0.56
Now,
Margin of error is given as:
E =
![2\sqrt{(p(1-p))/(n)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/qed0yqi2b09ar08o1mcbb0xn0vro4xubk6.png)
on substituting the respective values, we get
E =
![2\sqrt{(0.56(1-0.56))/(500)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/1lim7ilhl4qhzpc9jofy8dyikabnbehkd1.png)
or
E = 2 × 0.0222
or
E = 0.0444
And,
The resulting interval
= p ± E
= 0.56 ± 0.0444
= 0.5156 to 0.6044