Question

Light of a wavelength 610nm is incident on a slit of

0.20mmwide and the diffraction pattern is produced on a screen that
is1.5m from the slit. What is the width of the
centralmaximum?

Answer 1

0.00915 m

Step-by-step explanation:

`\lambda` = Wavelength of light = 610 nm

L = Distance of slit to screen = 1.5 m

a = Slit gap = 0.2 mm

Width of central maximum is given by

`w=(2\lambda L)/(a)\\\Rightarrow w=(2* 610* 10^(-9)* 1.5)/(0.2* 10^(-3))\\\Rightarrow w=0.00915\ m`

The width of the central maximum is 0.00915 m