Question

In a diffraction experiment, light of 600nm wavelengthproduces

a first-order maximum 0.350 mm from the central maximum ona distant
screen. A second monochromatic source produces athird-order maximum
0.870mm from the central maximum when it passesthrough the same
diffraction grating. What is the wavelengthof the light from the
second source?

Answer 1

497 nanometers is the answer.

λ^2=(y^2/,m^2)d/R=(y^2/m^2)(m^1/y^1) λ^1=(0.870mm/3)(1/0.350mm)600nm=497nm