Question

A 2.29N force is applied to the plunger of a hypodermicneedle.

If the diameter of the plunger is 1.27 cm and that ofthe needle is
0.181 mm, with what force does the fluid leave theneedle?

Answer 1

0.04651 N

Step-by-step explanation:

`F_1` = Force on plunger = 2.29 N

`d_1` = Diameter of plunger = 1.27 cm

`d_2` = Diameter of needle = 0.181 cm

`F_2` = Force on needle

From Pascal's law we have

`(F_1)/(A_1)=(F_2)/(A_2)\\\Rightarrow F_2=(F_1* A_2)/(A_1)\\\Rightarrow F_2=(2.29* \pi(0.181^2)/(4))/((\pi 1.27^2)/(4))\\\Rightarrow F_2=0.04651\ N`

The force with which the fluid leaves the needle is 0.04651 N