Answer:
0.0784 or 7.84%
Explanation:
Data provided in the question:
Probability that adults (age 18 and older) eat at a fast food restaurant about once a week, P(F) = 28% = 0.28
Now,
Probability that two randomly selected adults would both say they eat at a fast food restaurant about once a week
= First adult selected eats fast food × Second adult selected eats fast food
= 0.28 × 0.28
= 0.0784
or
= 0.0784 × 100%
= 7.84%