Answer:
![y=106.656*(0.816)^x](https://img.qammunity.org/2021/formulas/mathematics/middle-school/e2partb5gtbuwqql0nelin37wirzet8pn3.png)
Explanation:
The exponential equation will be of the form:
![y=ba^x.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/hvn3egwvn5rhf1g8xwu4g4itjrvb637oxt.png)
Now from the information give we have two points:
at
![y=58.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ejez05xk6h3yp64k7uqlc65uuhrhtj6d0i.png)
at
![y=14.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wtgsw3dhbxb69unyobybfuwan4fqbdcb60.png)
Thus we have two equations
![(1).58=ba^3,](https://img.qammunity.org/2021/formulas/mathematics/middle-school/oj2zf54kof9203nm2ac17k9fgo2f7sm2h5.png)
![(2).14=ba^(10).](https://img.qammunity.org/2021/formulas/mathematics/middle-school/l4r4aqy9hif7ke3issn019qazlg1xow3hp.png)
From equation
we solve for
:
![b=(58)/(a^3),](https://img.qammunity.org/2021/formulas/mathematics/middle-school/r207c9re8ld8s7mulcjghb0n6afr3wkool.png)
and put this value into equation
and we get:
![14=(58)/(a^3)*a^(10)=58a^7,](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yh3jewoqrb1pr5les9czfaj95z43zx3xgj.png)
and solve for
![a:](https://img.qammunity.org/2021/formulas/mathematics/middle-school/njj7nogxl3xzquz0lv901wo8gmyjmn4v2i.png)
![a=\sqrt[7]{(14)/(58) }=0.8162.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rsfsnlcutvjpppuoisitothy4r1ua54vf7.png)
![\boxed{a=0.816.}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/fvtlnoqc07enrli12wf228dnzm39r38oqk.png)
We now put this value into equation (1) and solve for
:
.
With values of
and
in hand, we have our exponential function:
![\boxed{y=106.656*(0.816)^x.}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/m370bqtnfmiexr3r9kjdf1k2z2rcaygz8k.png)