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5. What is the equation of the tangent line to the circle x^2+y^2=1 through the point (6,0)?

User Starnetter
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1 Answer

5 votes

Answer:

There is no tangent line of the given circle at (6, 0).

Explanation:

Given equation of the circle,


x^2 + y^2 = 1

∵ equation of a circle is
(x-h)^2 +(y-k)^2 = r^2,

Where, (h, k) is the center of the circle and r is the radius,

By comparing,

Center of the given circle = (0, 0),

Radius of the circle = 1 unit

Now, check whether point (6, 0) lie on the circle,

if x = 6,
6^2 + y^2 = 1


36 + y^2 = 1


y^2 = 1- 36


y= i√(35)\\eq 0

i.e., (6, 0) does not lie on the circle,

Hence, there is no tangent line of the given circle at (6, 0).

User INeelPatel
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