Question

5. Use a table of standard normal curve areas to find the following:

a. The area to the left of z = 0.56
b. The area to the right of z = 1.20
c. The area to the left of z = −1.47
d. The area to the right of z = −0.35
e. The area between z = −1.39 and z = 0.80
f. Choose a response from parts (a) through (f), and explain how you determined your answer.

Answer 1

a. 0.7123

b. 0.1151

c. 0.0708

d. 0.6368

e. 0.7058

Explanation:

• the area to the right of z* can be stated as P(z<z*), and corresponding probability of z* on z-table gives the result.

a. The area to the left of z = 0.56 = P(z<0.56) = 0.7123

b. The area to the right of z = 1.20 =P(z>1.20)= 1- P(z<1.20)= 1-0,8849=0.1151

c. The area to the left of z = −1.47 = P(z<-1.47)= 0.0708

d. The area to the right of z = −0.35 =P(z>-0.35) = 1-P(z<-0.35)=1-0,3632=0.6368

e. P(-1.39<z<0.80) = P(z<0.80) - P(z<-1.39) = 0.7881-0.0823 = 0.7058