Answer:
1. Amino acid sequence-
Met-Ala-Ile-Cys-Leu-Phe-Gln-Ser-Leu-Ala-Ala-Gln-Asp-Arg-Pro-Gly
2. N terminal - 5' end (Met) and C terminal- 3' end (Gly)
Step-by-step explanation:
1. The process of translation proceeds in 5' to 3' direction when the codon or triplets of bases are read by the tRNA. The tRNA gets charged with methionine and brings the methionine to find the start codon called AUG.
In the given question, the tRNA will first find the start codon called AUG and then add further amino acids. Each codon code for a particular amino acid.
The sequence formed will be-
Met-Ala-Ile-Cys-Leu-Phe-Gln-Ser-Leu-Ala-Ala-Gln-Asp-Arg-Pro-Gly
2. The peptide structure contains the free amino group at one end called n terminal which is present at the 5' end and the free Carboxyl group at 3' end called C terminal.
Thus, the amino acid at N terminal will be- methionine and at C-terminal will be- Glycine.