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Moo bikes 5 1/2 miles and Nathan mike 3 1/2 miles. How many times the length of nathan’s bike ride was moo’s bike ride

User Flow
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1 Answer

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(11)/(7) times the length of nathan’s bike ride was moo’s bike ride

Solution:

Given that, Moo bikes
5(1)/(2) miles and Nathan mike
3(1)/(2) miles

To find: number of times the length of nathan’s bike ride was moo’s bike ride

From given question,

Length of Moo bike ride =
5(1)/(2) miles


\rightarrow 5(1)/(2) = ( 2 * 5 + 1)/(2) = (11)/(2) \text{ miles }

Length of nathan bike ride =
3(1)/(2) miles


\rightarrow 3(1)/(2) = (2 * 3 + 1)/(2) = (7)/(2) \text{ miles}

Number of times the length of nathan’s bike ride was moo’s bike ride is given by:

Let "n" be the number of times

Therefore,

Length of Moo's bike ride = n x Length of nathan bike ride


(11)/(2) = n * (7)/(2)\\\\11 = 7n\\\\n = (11)/(7)

Thus
(11)/(7) times the length of nathan’s bike ride was moo’s bike ride

User Mark Willis
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