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Determine whether the Mean Value Theorem applies to the function f(x)=2x^1/5 on the interval [-32, 32]

User Chandan
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Answer

given,


f(x) = 2 x^(1/5)

interval = [-32, 32]

differentiating the given equation


f'(x) = (d)/(dx)(2 x^(1/5))


f'(x) = (2)/(5x^(4/5))

hence, the above solution is not defined at x = 0

and x = 0 lie in the given interval i.e. [-32, 32]

so, at x = 0 the function is not differentiable.

Hence, mean value theorem does not apply to the given function.

User Paritosh Kulkarni
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