Answer:
There are 175,223,510 ways.
Explanation:
If the order of the white balls doesnt metter, we have as many possibilities to pick white balls as ways of pick 5 elements from a set of 59. That number is the combinatorial number of 59 with 5 given by
![{59 \choose 5} = (59!)/((59-5)!5!) = 5,006,386](https://img.qammunity.org/2021/formulas/mathematics/high-school/gzw6j2torsz7b5azm0ibqrhexq2plvvkly.png)
We have 35 different ways to pick the red ball. Combining both events, we have
35*5,006,386 = 175,223,510
ways of picking the 5 numbers and the bonus one.