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The length of a rectangular garden is 4 more than three times the width. If the perimeter of the garden 104 feet, what are the dimensions of the garden.

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User Ischenkodv
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Answer:

12 ft by 40 ft

Explanation:

Let L represent the length and W the width. Then L = 3W + 4.

The perimeter formula is P = 2L + 2W or P = 2(L + W).

Substituting 104 ft for P, we get 104 ft = 2(L + W), which reduces to

52 ft = L + W, or 52 ft = 3W + 4 + W.

Therefore, 52 ft = 4W + 4.

Solving this for W, we get 48 ft = 4W, or W = 12 ft.

Then, because L = 3W + 4, L = 3(12 ft) + 4 = 40 ft = L

The dimensions of the garden are 12 ft by 40 ft.

User Estanford
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