70.5k views
4 votes
Prove that Zn Zn is notisomorphic to any subgroup of Zm for any m.

1 Answer

5 votes

Answer and Step-by-step explanation:

Every group homomorphism ϕ:Zn→Zm extends in a unique way to a linear transformation T:Qn→Qm of vector spaces over Q.

Moreover, ϕ is injective iff T is injective. But T being injective implies n≤m.

Applying this to both ϕ and ϕ−1, we conclude that n≤m≤n.

NOTE:

The proof and step-by-step explanation is in the attachment below

Prove that Zn Zn is notisomorphic to any subgroup of Zm for any m.-example-1
User Kaylum
by
5.7k points