The numbers are 1 and 18
Solution:
Let the smaller number be "x"
Let the larger number be "y"
Given that smaller of two numbers is five less than
the larger number
smaller number = one - third of larger number - 5
![x = (1)/(3) * y - 5\\\\x = (y - 15)/(3)\\\\](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tgy72i6x3fon3nn5hvv6xze7q8zwd2ku0g.png)
3x = y - 15
y = 3x + 15 ------- eqn 1
Half the larger added to the smaller is 10
![(1)/(2)y + x = 10\\\\(y + 2x)/(2) = 10](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vooxm6yqu0dxhaukceqpltdiud43nkpi88.png)
y + 2x = 20 ------- eqn 2
Let us solve eqn 1 and eqn 2
Substitute eqn 1 in eqn 2
3x + 15 + 2x = 20
5x = 20 - 15
5x = 5
x = 1
From eqn 1,
y = 3(1) + 15 = 18
y = 18
Thus the numbers are 1 and 18