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The smaller of two numbers is five less than 1/3 the larger number. Half the larger added to the smaller is 10. Find the numbers.

User Jit B
by
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1 Answer

4 votes

The numbers are 1 and 18

Solution:

Let the smaller number be "x"

Let the larger number be "y"

Given that smaller of two numbers is five less than
(1)/(3) the larger number

smaller number = one - third of larger number - 5


x = (1)/(3) * y - 5\\\\x = (y - 15)/(3)\\\\

3x = y - 15

y = 3x + 15 ------- eqn 1

Half the larger added to the smaller is 10


(1)/(2)y + x = 10\\\\(y + 2x)/(2) = 10

y + 2x = 20 ------- eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 1 in eqn 2

3x + 15 + 2x = 20

5x = 20 - 15

5x = 5

x = 1

From eqn 1,

y = 3(1) + 15 = 18

y = 18

Thus the numbers are 1 and 18

User Neal Stublen
by
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