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Convert x2 + y2 -4x = 0 to polar form.

User ArisRS
by
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1 Answer

4 votes

Answer:


r(r-4\cos \theta)=0

Explanation:

We are given the following equation:


x^2 + y^2 -4x = 0

We have to convert it into polar form.

We put


x = r \cos \theta\\y = r\sin \theta

Putting values, we get:


x^2 + y^2 -4x = 0\\(r\cos \theta)^2 + (r\sin \theta)^2 - 4(r\cos \theta) = 0\\r^2(\cos^2 \theta + \sin^2 \theta) - 4r\cos \theta = 0\\r^2 - 4r\cos \theta = 0\\r(r-4\cos \theta)=0

is the required polar form.

User GSite
by
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