Question

An engineer traveled 130 mi by car and then an additional 690 mi

by plane. The rate of the plane was three times the rate of the
car. The total trip took 6 h. Find the rate of the car.

Answer 1

60 mph

Explanation:

Distance by car = 130 mi

Distance by plane = 690 mi

Total travel time = 6 h

R(p) = 3R(c)

The total travel time can be described by the following equation:

`(130)/(R(c))+ (690)/(3R(c))=6\\ 6R(c) = 130 +230\\R(c) = 60\ mph`

The rate of the car was 60 mph.