A triangular room has sides of length 3.8 m, 5.1 m, and 5.1 m. What is the area of the room?

Question

asked Feb 26, 2021 163k views

1 Answer

Lauretta · Answer 1 · 2021-03-02T20:24:14+0000

Explanation:

Area of triangle is with side a,b and c is given by

A=√(s* (s-a)* (s-b)* (s-c))

where
s=(a+b+c)/(2)

Here

a = 3.8 m

b = 5.1 m

c = 5.1 m

$s=(a+b+c)/(2)\\\\s=(3.8+5.1+5.1)/(2)\\\\s=7$

Substituting in area equation

$A=√(s* (s-a)* (s-b)* (s-c))\\\\A=√(7* (7-3.8)* (7-5.1)* (7-5.1))\\\\A=√(7* 3.2* 1.9* 1.9)\\\\A=√(80.864)\\\\A=8.99m^2$

Area of triangle is 8.99 m²