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A horizontal force of 199 N is applied to move a 55-kg cart (initially at rest) across a 8 m level surface. What is the final speed of the cart?

User Alwin
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1 Answer

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Answer:

Final speed will be 7.60 m /sec

Step-by-step explanation:

We have given horizontal force F = 199 N

Mass of the cart = 55 kg '

From newton's law acceleration will be
a=(F)/(M)=(199)/(55)=3.618m/sec^2

As initially cart is at rest so initial velocity u = 0 m/sec

Distance traveled s= 8 m

From third equation of motion


v^2=u^2+2as


v^2=0^2+2* 3.618* 8

v = 7.60 m /sec

User David Clews
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