65.2k views
4 votes
Find all the zeros for each function P(x)=x^4-4x^3-x^2+20x-20

1 Answer

1 vote

Answer:

The zeros of the given polynomial function are

2,2,
\pm√(5)

Explanation:

Given polynomial is
P(x)=x^4-4x^3-x^2+20x-20

To find the zeros equate the given polynomial to zero

ie., P(x)=0


P(x)=x^4-4x^3-x^2+20x-20=0

By using synthetic division we can solve the polynomial:

2_| 1 -4 -1 20 -20

0 2 -4 -10 20

_____________________

1 -2 -5 10 |_0

Therefore x-2=0

x=2 is a zero of P(x)

Now we can write the cubic equation as below:


x^3-2x^2-5x+10=0

Again using synthetic division

2_| 1 -2 -5 10

0 2 0 -10

______________

1 0 -5 |_0

Therefore x-2=0

x=2 is also a zero of P(x).

Now we have
x^2+0x-5=0


x^2-5=0


x^2=5


x^=\pm√(5) is a zero of P(x)

Therefore the zeros are 2,2,
\pm√(5)

User Coco Puffs
by
6.4k points