Answer:
The zeros of the given polynomial function are
2,2,
Explanation:
Given polynomial is

To find the zeros equate the given polynomial to zero
ie., P(x)=0

By using synthetic division we can solve the polynomial:
2_| 1 -4 -1 20 -20
0 2 -4 -10 20
_____________________
1 -2 -5 10 |_0
Therefore x-2=0
x=2 is a zero of P(x)
Now we can write the cubic equation as below:

Again using synthetic division
2_| 1 -2 -5 10
0 2 0 -10
______________
1 0 -5 |_0
Therefore x-2=0
x=2 is also a zero of P(x).
Now we have



is a zero of P(x)
Therefore the zeros are 2,2,