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The square root of a number consisting of two digits isequal

to the sum of the digits and is less than the number obtainedby
interchanging the digits by 9. Find the number.

User Bera
by
5.1k points

1 Answer

0 votes

Answer:

81

Explanation:

Let the digits that make up the number be a and b.

Given that the square root of the number is equal to the sum of the digits.

Then,

√(10a + b) = a + b

Also given that the square root of the number is less than the number obtained by interchanging the digits by 9, then

√(10a +b) + 9 = 10b + a

Since √(10a + b) = a + b, then

a + b + 9 = 10b + a

a - a + 9 = 10b - b

9b = 9

b = 1

since √(10a + b) = a + b

√(10a + 1) = a + 1

10a + 1= (a + 1)²

10a + 1 = a² + 2a + 1

a² + 2a - 10a + 1 - 1 = 0

a² - 8a = 0

a(a - 8) = 0

a = 0 or a = 8

Using a = 8 and b = 1,

the number 10a + b = 10(8) + 1 = 81.

User Piohen
by
4.6k points