Answer:
Object will be at a distance of 358098.6 km from the source
Explanation:
We have given angle = 0.0008 degree
![=(0.0008* \pi )/(180)=4.444* 10^(-6)\pi](https://img.qammunity.org/2021/formulas/mathematics/college/sc7ez0z1jfu40vuo8dahfe4ysviifxzquk.png)
Radius is given = 2.50 km
Linear size of the object will be equal to diameter
So linear size = 2.5×2 = 5 km
We know that linear size
![=distance * \Theta](https://img.qammunity.org/2021/formulas/mathematics/college/wbhcsuj676143hnksv0grgtp6ef2v8ja7t.png)
So
![5=d* 4.444* 10^(-6)\pi](https://img.qammunity.org/2021/formulas/mathematics/college/inlli4hecezo3m9gq7c50rdzif3hm6k2x9.png)
d = 358098.6 km