Answer:
sin(B) = 12/13
cos(B) = 5/13
tan(B) = 12/5
csc(B) = 13/12
sec(B) = 13/5
cot(B) = 5/12
Explanation:
If ABC is a right triangle, assuming that ∠C = 90°, then the segment AB =13 is the hypotenuse and the other two sides are:

The six trigonometric functions of angle B are:
