Answer:
Explanation:
The "fundamental theorem of algebra" tells you a polynomial has a number of roots equal to its degree. Those roots are not always rational or real, but are always members of the set of complex numbers.
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The given equation can be put into vertex form as ...
2(x -1)^2 -3 = 0
It will have roots ...
1 ± √(3/2) = (2±√6)/2
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If you don't like to mess with translating a quadratic to vertex form, you can use the quadratic formula:
x = (-b±√(b²-4ac))/(2a) . . . . . for a=2, b=-4, c=-1
x = (4 ± √(16+8))/(2·2) = (4 ± 2√6)/4 = (2±√6)/2