Answer:
(a)

(b)

(c) Answer of part a is equation of line
which is parallel to y axis and in part by equation of line is
which is parallel to x axis
Explanation:
We have given points are

(a) Equation of line is given x = -9
We have to find the equation of line parallel to x= -9 and passing through

x = -9 line is parallel to y axis and so slope will be infinite
Equation of line is given by

So


(b) Equation of line is given

This line is parallel to x axis so slope will be zero
So equation of line will be


(c) Answer of part a is equation of line
which is parallel to y axis and in part by equation of line is
which is parallel to x axis