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What is the perimeter, P, of a rectangle that has a length of x + 8 and a width of y-1?

1 Answer

6 votes

Answer:

Explanation:

Perimeter = 2*(length +width)

P = 2*( x+8 + y-1)

P = 2*(x + y + 7)

P =2x + 2y + 17

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