Question

How many moles of ammonium nitrate (NH4NO3) are required to decompose to produce 0.90 moles of water (H2O)?

Answer 1

The answer to your question is 0.45 moles

Step-by-step explanation:

Balanced equation

NH₄NO₃ ⇒ N₂O + 2H₂O

2 ----------- N ----------- 2

4 ------------ H ----------- 4

3 ------------ O ----------- 3

From the balanced equation we know that 1 mol of NH₄NO₃ produces 2 moles of water, so we use proportions to find the amount of NH₄NO₃ required to produce 0.9 moles of water.

1 mol of NH₄NO₃ ------------- 2 moles of water

? -------------- 0.9 moles of water

Use cross multiplication

x =
`(0.9 x 1 )/(2)`

Simplification

x = 0.9 / 2

Result

x = 0.45 moles of NH₄NO₃