Question

8.
How many molecules of OF2, would have a mass of 0.132 g?

Answer 1

Answer : The number of molecules of
`OF_2` is,
`1.47* 10^(21)`

Explanation :

First we have to calculate the moles of
`OF_2`

`\text{Moles of }OF_2=\frac{\text{Mass of }OF_2}{\text{Molar mass of }OF_2}`

Molar mass of
`OF_2` = 54 g/mol

`\text{Moles of }OF_2=(0.132g)/(54g/mol)=0.00244mol`

Now we have to calculate the number of molecules of
`OF_2`

As, 1 mole of
`OF_2` contains
`6.022* 10^(23)` number of
`OF_2` molecules

So, 0.00244 mole of
`OF_2` contains
`0.00244* 6.022* 10^(23)=1.47* 10^(21)` number of
`OF_2` molecules

Thus, the number of molecules of
`OF_2` is,
`1.47* 10^(21)`