Question

Stacy and David are having a tug-of-war by pulling on opposite ends of a 5.0 kg rope. Stacy pulls with a 15. N force. What is David's force if the rope accelerates toward Stacy at 2.0 m/s^2?

Answer 1

`F_(David) = 5N`

Step-by-step explanation:

If the rope accelerates toward Stacy, then the force David applies is less than that of Stacy does.

By Newton’s Second Law the net force can be calculated.

`F_(net) = ma = 5*2 = 10`

In that case, David pulls with 15 - 10 = 5N in order the rope to accelerate at 2 m/s^2.