4. 213.4 grams of NaNO3 contain how many moles?

asked Jan 20, 2021 103k views

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Answer:

Step-by-step explanation:

mass of NaNO3 = 213.4g

Molar mass = {23 + 14 + 3(16)}

= 23 + 14 + 48

= 85g/mol

Amount = mass/molar mass

= 213.4/85

= 2.5moles of NaNO3

Oleks answered Jan 27, 2021

by Oleks

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