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Solve each trigonometric equation such that 0 ≤ x ≤ 2????. Give answers in exact form.

a. 2 sin(x) + √3 = 0
b. tan2(x) − 1 = 0

1 Answer

4 votes

Answer:

(a)
x=(5\pi )/(3)

(b)
x=(\pi )/(8)

Explanation:

It is given that
0\leq x\leq 2\pi

(a) We have given equation
2sinx+√(3)=0


sinx=(-√(3))/(2)


x=sin^(-1)(-0.866)


x=(-\pi )/(3)=2\pi -(\pi )/(3)=(5\pi )/(3)

(b)
tan(2x)=1


2x=tan^(-1)1


2x=(\pi )/(4)


x=(\pi )/(8)

User Jtymann
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