Answer:
11 marbles.
Explanation:
Given: Total number of marbles= 21.
The number of blue marbles is 9 less than 2 times the number of red marbles.
Now, finding the number of blue marbles.
Lets assume the number of red marbles be "x".
∴ number of blue marbles=
= (2x-9)
As given total number of marbles is 21.
we can write,
![x+ (2x-9)= 21](https://img.qammunity.org/2021/formulas/mathematics/college/fnbt23dx620stqcjp9ughxmcjui1k459v9.png)
Opening parenthesis.
⇒
![3x-9= 21\ marbles](https://img.qammunity.org/2021/formulas/mathematics/college/xlgx1ku5095qpljrxvezflqsrkbtsdnjdi.png)
Adding 9 on both side.
⇒
![3x= 30](https://img.qammunity.org/2021/formulas/mathematics/college/yq1m4spbi1zh3ecamta2j9fr8nv2irnici.png)
cross multiplying both side
∴ x=
![(30)/(3) = 10\ marbles](https://img.qammunity.org/2021/formulas/mathematics/college/iee6z8qfa6yz1x0xn76lgsznf3ku6mepoz.png)
Red marbles= 10 marbles.
Now, subtituting the number of red marbles to find number of blue marbles.
Blue marbles= (2x-9)
Number of blue marbles=
![( 2* 10-9)= 20-9](https://img.qammunity.org/2021/formulas/mathematics/college/7f4k2q7u9y51c9u9kfjcxp3kaaet18m0m1.png)
∴ Number of blue marbles= 11 marbles.