Answer:
Explanation:
a) The diagram representing this situation is shown in the attached photo.
V represents the position of Valerie.
S represents the position of the school.
Y represents the position of Yuri.
b) v represents the distance of Yuri from the school. To determine v, we would apply the cosine rule,
a^2 = b^2 + c^2 - 2bcCosA
Therefore,
v^2 = 3^2 + 2^2 - 2 × 3 × 2Cos45
v^2 = 11 - 12 × 0.7071
v^2 = 11 - 8.42 = 2.58
v = √2.58
v = 1.61
c) to fine angle Y, we would apply
the sine rule. It is expressed as
a/sinA = b/sinB = c/sin C
2/SinY = 1.61/Sin45
2Sin45 = 1.61SinY
2 × 0.7071 = 1.61SinY
SinY = 1.4034/1.61 = 0.8717
Y = 60.66 degrees
The bearing of the school from Yuri's house would be
180 - 15.66 = 164.34 degrees