Question

What is strength of the electric field between two parallel conducting plates separated by 1.00 cm and having an electric potential difference between them of 15,000 V?

Answer 1

Electric field will be
`1.5* 10^(6)V/m`

Step-by-step explanation:

We have given potential difference between the two plates = 15000 volt

Distance between the plates =
`d=1cm=10^(-2)m`

We have to find the electric field strength between the plates

Potential difference between the plates is equal to
`V=Ed`

So electric field strength will be
`E=(V)/(d)=(15000)/(10^(-2))=1.5* 10^(6)V/m`

So electric field will be
`1.5* 10^(6)V/m`