Question

Evaluate \dfrac14c+3d

4
1
​
c+3dstart fraction, 1, divided by, 4, end fraction, c, plus, 3, d when c=6c=6c, equals, 6 and d=7d=7

Answer 1

Answer:45/2

Step-by-step explanation:.

Answer 2

Answer:
`(45)/(2)`

Explanation:

The exercise is: " Evaluate
`(1)/(4)c + 3d` when
`c = 6` and
`d = 7`

Given the following expression:

`(1)/(4)c + 3d`

You can follow these steps in order to evaluate it:

1. Substitute
`c = 6` and
`d = 7` into the expression provided in the exercise:

`(1)/(4)(6) + 3(7)`

2. Solve the multiplications. Remember that:

`(a)/(b)*(c)/(d)=(ac)/(bd)`

Then:

`=(6)/(4) +21`

3. Reduce the fraction. Notice that the numerator 6 and the denomiantor 4 can be both divided by 2. Then:

`=(3)/(2) +21`

4. Solve the addition:

`=(3)/(2) +(21)/(1)`

Since the number 21 has a denominator 1, the Least Common Denominator is:

`LCD=2`

Then, the sum is:

`=(3+42)/(2)=(45)/(2)`