Answer:
There will 6.38 mg of NH3 extert the same pressure as 12.8 mg H2S
Step-by-step explanation:
Step 1: Data given
Mass of hydrogen sulfide (H2S)= 12.8 mg = 0.0128 grams
Molar mass of H2S = 34.1 g/mol
Step 2: Calculate moles of H2S
Moles of H2S = Mass H2S / molar mass H2S
Moles H2S = 0.0128 grams / 34.1 g/mol
Moles H2S = 3.75 * 10^-4
Gases here, exert exacty the same amount of pressure per mole as any other gas.
The ammonia will exert the same pressure as the hydrogen sulfide when the moles of ammonia equal the moles of hydrogen sulfide
Step 3: Calculate moles of NH3
Moles of H2S = moles of NH3
moles of NH3 = 3.75 * 10^-4
Step 4: Calculate mass of NH3
Mass of NH3 = moles NH3 * molar mass NH3
Mass of NH3 = 3.75 *10^-4 moles * 17.03 g/mol
Mass of NH3 = 0.00639 grams = 6.38 mg
There will 6.38 mg of NH3 extert the same pressure as 12.8 mg H2S