The solution of
is
![(1)/(28) \text{ or } 0.0357](https://img.qammunity.org/2021/formulas/mathematics/middle-school/url435we2vz60oj2s9u791lik4mv17c74j.png)
Solution:
Given that we have to find the solution of
![(3)/(4) - (5)/(7)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rv0n8ucfovffeg3kajdizcg4xd5lbonm5v.png)
To solve the given sum, first make the denominators of both the fractions same
This can be done by taking L.C.M of both denominators
Step 1:
L.C.M of 4 and 7:
The prime factor of 4 = 2 x 2
The prime factor of 7 = 7
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 7
Multiply these factors together to find the LCM
LCM = 2 x 2 x 7 = 28
Thus L.C.M of denominators is 28
Step 2:
Solution of
![(3)/(4) - (5)/(7)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rv0n8ucfovffeg3kajdizcg4xd5lbonm5v.png)
Multiply the denominator by a number to get 28 and multiply that same number with numerator also
![(3)/(4) - (5)/(7) = (3 * 7)/(4 * 7) - (5 * 4)/(7 * 4)=(21)/(28) - (20)/(28)\\\\(21)/(28) - (20)/(28) = (21-20)/(28) = (1)/(28)\\\\(1)/(28) = 0.0357](https://img.qammunity.org/2021/formulas/mathematics/middle-school/frnkl8m8kppifvf0xt98dbhdiwnzyyj3t1.png)
Thus solution of
is
![(1)/(28) \text{ or } 0.0357](https://img.qammunity.org/2021/formulas/mathematics/middle-school/url435we2vz60oj2s9u791lik4mv17c74j.png)