Question

Find the measure of angle P in the triangle below.

Answer 1

Explanation:

Sin (angle p) = 48/60 = 4/5 = 0.8

angle p = sin∧-1 0.8 = 53.13010235

Answer 2

53.13°

Explanation:

It the given triangle PQR,

`p=48,q=60,r=36`

Cosine formula:

`\cos A=(b^2+c^2-a^2)/(2bc)`

We need to find the measure of angle P.

`\cos P=(q^2+r^2-p^2)/(2qr)`

Substitute the given values.

`\cos P=((60)^2+(36)^2-(48)^2)/(2(60)(36))`

`\cos P=(2592)/(4320)`

`\cos P=0.6`

`P=\cos^(-1)(0.6)`

`P\approx 53.13`

Hence, the measure of angle P is 53.13 degrees.