Question

A 90.0kg person stands 1.25m from a 60.0kg person sitting on a bench nearby. What is the magnitude of the gravitational force between them ?

Answer 1

Answer:
`23(10)^(-8) N`

Step-by-step explanation:

According to Newton's law of Gravitation, the force
`F` exerted between two bodies of masses
`m1` and
`m2` and separated by a distance
`r` is equal to the product of their masses and inversely proportional to the square of the distance:

`F=G((m1)(m2))/(r^2)` (1)

Where:

`G=6.674(10)^(-11)(m^(3))/(kgs^(2))` is the Gravitational Constant

`m1=90 kg` is the mass of the first person

`m2=60 kg` is the mass of the second person

`r=1.25 m` is the distance between both persons

Solving:

`F=6.674(10)^(-11)(m^(3))/(kgs^(2))((90 kg)(60 kg))/((1.25 m)^2)` (2)

Finally:

`F=23(10)^(-8) N` This is the gravitational force between both persons. As you can see is too small.