Question

What is the escape velocity on the planet Mars? Mars' mass is 6.46*10^ 23 kg and radius is 3.39*10^ 6 m. .

Answer 1

Answer:5041.90 m/s

Step-by-step explanation:

The escape velocity equation is:

`V_(e)=\sqrt{(2GM)/(R)}` (1)

Where:

`V_(e)` is the escape velocity

`G=6.67(10)^(-11) Nm^(2)/kg^(2)` is the Universal Gravitational constant

`M=6.46(10)^(23)kg` is the mass of Mars

`R=3.39(10)^(6) m` is Mar's radius

Solving:

`V_(e)=\sqrt{(2(6.67(10)^(-11) Nm^(2)/kg^(2))(6.46(10)^(23)kg))/(3.39(10)^(6) m)}` (2)

Finally:

`V_(e)=5041.90 m/s` This is the escape velocity on Mars