Question

If the circuit is capacitive reactance measured 650 Ω and its resistance measures 1,200 Ω, what is the phase angle between circuit voltage and current?

Answer 1

`\phi=28.4^(\circ)`

Step-by-step explanation:

We are given that

Capacitive reactance=
`X_c=650\Omega`

Resistance of circuit= R=
`1200\Omega`

We have to find the phase angle between circuit voltage and current.

We know that

Phase angle,
`\phi=tan^(-1)((X_c)/(R))`

By using this formula we will find the phase angle between voltage and current of circuit.

Substitute the values then we get

`\phi=\tan^(-1)((650)/(1200))`

`\phi=\tan^(-1)(0.54)`

`\phi=28.4^(\circ)`

Hence, the phase angle between circuit voltage and current=28.4 degrees