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Which expression represents the equation of the parabola with focus of (-3,3) and directrix y

User Enayat
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Answer:

Equation of the parabola with focus of (-3,3) and directrix y


(x+3)^(2)=4a(y+a-3)

Explanation:

As directix is not give so writing it in form of a.

Standard equation for parabola with directix is y = k - a and focus (h,k+a)


(x-h)^(2)=4a(y-k)---(1)

Given that focus is (-3, 3)

(-3, 3) = (h, k +a)

by comparison

h= -3

k+a = 3

a = 3 - a

Substituting this value in (1)


(x-(-3))^(2)=4a(y-(3-a))\\(x+3)^(2)=4a(y+a-3)\\

User Ferran Maylinch
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